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I have copied this code from somewhere and am trying to modify it for my needs. It was designed for bash but I am running it under zsh.

I always have trouble running bash scripts under zsh, as there seems to be quite a few differences between the two languages(?). Is anyone able to tell me what I need to modify here so that it works with zsh?

declare -a files=(
  "$HOME/.dotfiles/bash/exports" # Exports
  "$HOME/.dotfiles/bash/aliases" # Aliases
  "$HOME/.dotfiles/bash/functions" # Functions
  "$HOME/.z.sh" # z binary from https://github.com/rupa/z
  "$NVM_HOME/nvm.sh" # NVM
  "$ZSH/oh-my-zsh.sh"
)

# If these files are readable, source them
for index in ${!files[*]}
do
  if [ -r ${files[$index]} ]; then
    source ${files[$index]}
  fi
done

unset files
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2 Answers

up vote 1 down vote accepted

Here's a ~/.zshrc that sources a bunch of other files:

# Load the zsh files. 
# This is taken from Frank Terbeck's ZSH setup.
for rc in ~/.zshrc.d/???-*.z; do
    if [[ -r ${rc} ]] ; then
        zprintf 1 "zshrc: loading %s\n" "$rc"
        source "$rc"
    else    
        zprintf 0 "zshrc: could not load %s\n" "$rc"
    fi      
done    
unset rc

This'll source files in ~/.zshrc.d/ which have a filename beginning with a 3-digit number (for example, 421-Name.zsh).

The advantage of this method is that it allows you to have a single directory (~/.zshrc.d/) containing all your startup-scripts. You can then add to / remove from that directory without having to touch multiple files (you don't have to edit ~/.zshrc every time you add a script).

To change the filenames, edit this line:

for rc in ~/.zshrc.d/???-*.z; do

The directory it's searching is ~/.zshrd.d/. If you don't want a 3-digit prefix, remove the ???-. The extension (.z) can also be changed here.

Note: the ? doesn't actually match a digit, my mistake. From man zshexpn:

?      Matches any character.
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This looks good! What if I didn't want to have the requirement of a 3-digit prefix? –  Oliver Joseph Ash Jan 6 '13 at 11:23
    
@OliverJosephAsh Added a comment to the answer. –  simont Jan 6 '13 at 23:08
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I'm more familiar with bash than zsh, but this should work in either:

# zsh's declare (/typeset) command doesn't allow arrays to be assigned as
# they're declared. Actually, arrays don't really have to be declared, you can
# just create them by assigning an array value; but for completeness...
declare -a files
# Comments aren't recognized inside an array declaration, so leave them out
files=(
    "$HOME/.dotfiles/bash/exports"
    "$HOME/.dotfiles/bash/aliases"
    "$HOME/.dotfiles/bash/functions"
    "$HOME/.z.sh"
    "$NVM_HOME/nvm.sh"
    "$ZSH/oh-my-zsh.sh"
)

# If these files are readable, source them
# Note: rather than iterating over a list of array indexes and using them to
# pull out the array elements, I've switched this to iterating over the array
# elements directly. It's simpler, and works the same in both bash and zsh.
for file in "${files[@]}"
do
    if [ -r "$file" ]; then
        # Note that if any of the files have bashisms, they may break in zsh
        source "$file"
    fi
done

unset files
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