Super User is a question and answer site for computer enthusiasts and power users. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I have this line in a function I'm adapting from a bash function into zsh function:

local info=( $(command df -P $fs | awk 'END{ print $2,$3,$5 }') )

Whenever I call it in the func I get this:

mydf:9: bad pattern: info=( 712687280

But when I call it from the shell I get the expected answer:

$ info=($(command df -P $fs | awk 'END{ print $2,$3,$5 }'))
$ echo $info                                                                                      
712687280 166242288 25%

I am 2 days into zsh so I'm a little ignorant as to what's causing the problem.

share|improve this question
up vote 6 down vote accepted

Put the assignment on a separate line from the local definition:

local info
info=( $(command df -P $fs | awk 'END{ print $2,$3,$5 }') )
share|improve this answer
1  
Could you please elaborate why the separate line is needed? I see it is working on zsh 5.1.1 (Cygwin), but fails on 5.0.2 (Linux). – Alexander Groß Dec 21 '15 at 0:36
1  
@AlexanderGroß when declaring and setting a local variable in a single command, apparently the order of operations is to first set the variable, and only afterwards restrict it to local scope. Try this: – Chauncey Garrett Jan 29 at 19:33
    
local unexpected=$(exit 1) && echo $? # 0 – Chauncey Garrett Jan 29 at 19:37
    
local expected && expected=$(exit 1) && echo $? # 1 – Chauncey Garrett Jan 29 at 19:38

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .