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I'm programming in Java and I want to use regex to look for any data with a percent sign, e.g. 10%, 20%,30%,etc. I've tried a.matches("%")but that only returns true if the string matches exactly the percent sign. What should be the correct regular expression to use? Thanks

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closed as off topic by Brad Patton, Sathya Apr 26 '13 at 2:46

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that gave me an error but a.matches("%*") works! thanks! –  newbie Apr 26 '13 at 2:28
    
This guide appears to be better than my suggestion. In java the wildcard is actually . apparently (I know little of Java). –  nerdwaller Apr 26 '13 at 2:31

1 Answer 1

If you're just looking for a '%', then String.indexOf('%') would probably be faster and simpler than any regular-expression-based solution.

Considering regular expressions, the matches() function attempts to match the entire string to the pattern, as you've discovered. Matcher.find() will look for substrings within the string that match the pattern, for example:

Pattern pp = Pattern.compile("%");
Matcher mm = Pattern.matcher(someString);
if (mm.find()) {
    // someString contains a '%'
    ...
}
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