I'm a newbie at this so please bear with me.
I've setup a server with Windows Server 2012 and I have 2 clients (my Laptop and my PC, just to give you the context). I will not demand to access the program twice. I use the server mainly as a file server.
What I want is to be able to safely disconnect from a RemoteApp without closing it and without "restarting" it. I want to be able to "continue" the application just as I can continue a remote desktop connection.
I've read Windows 2008 Server RemoteApp. How to keep the app running after disconnected from the server and I think it is a similar question, but for one the Windows version is different and for the other I have already managed to run a remote application by making a few entries in the servers registry and creating the RDP-file (and modify it).
So let's say the program I want to keep "open" even after disconnect is xchat or mirc... imagine I've joined some channels and then decided I want to shutdown my client, but I don't want to shutdown the application. I just disconnect and continue from my Laptop. How would I go about this? At the moment I've got the impression that I "hacked" my way solution (following this: http://geekswithblogs.net/twickers/archive/2009/12/18/137048.aspx), but even if I disconnect using tsdiscon from the server console, once I reconnect the connection of this program is reset (as if the program is started anew).
My server is not a AD DS server, because I don't think I need a domain at all nor am I saving profiles on my server. How can I make use of RemoteApp properly if possible - or is there perhaps some other way to accomplish this?
Thank you all in advance!