Take the 2-minute tour ×
Super User is a question and answer site for computer enthusiasts and power users. It's 100% free, no registration required.

How do I make GnuPG (specifically version 1.4.12) display the full, 64-bit (8-byte) key ID for a key on a keyring on my system?

Doing gpg --list-keys --fingerprint XXXXXXXX only displays the 32-bit portion of the key ID, which I already know, and the fingerprint (which at least in the past has not necessarily been the same as the key ID, although the rightmost 32 bits do match in this particular case).

Googling turned up some pages about the importance of specifying the 64-bit key ID to minimize the risk of collisions, and some GnuPG options which want or accept a long key ID, but I couldn't find anything about how to actually display the long key ID.

share|improve this question

2 Answers 2

up vote 7 down vote accepted

Alternatively you can use:

gpg --keyid-format LONG -k 0xDEADBEEF


gpg --keyid-format 0xLONG -k 0xDEADBEEF
share|improve this answer
This is actually even better IMO, as the output is much more readable than in Paulo's suggestion (which is still valid). –  Michael Kjörling Sep 30 '13 at 7:21
Yeah, I prefer the longer format so much that I have "keyid-format 0xLONG" in my gpg.conf so I don't have to specify it each time. Using --keyid-format 0xSHORT will display keys the default way. –  Ben Sep 30 '13 at 8:56

You can see the long key ID using the option --with-colons (yes, very intuitive).

To print only the long key ID, use something like:

$ gpg --list-keys --with-colons XXXXXXXX | awk -F: '/^pub:/ { print $5 }'
share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.