Take the 2-minute tour ×
Super User is a question and answer site for computer enthusiasts and power users. It's 100% free, no registration required.

I want to write a shell script or alias to find the number of different types of files in a directory. For example, sample output of script should be:

*.h      20
*.c      40
*.cpp    10
Makefile 3
share|improve this question

1 Answer 1

up vote 7 down vote accepted
find . -type f -name '*.*' -exec sh -c 'echo ${0##*.}' {} \; | sort | uniq -c | sort -nr

The echo ${0##*.} gives you the extension of the file. We pipe the output to sort and then count the unique lines with uniq.

Some additions:

  • Since the output of uniq is not sorted according to the number of occurrences, you'll have to pipe again into a numeric sort (-nr) if you want it sorted.
  • If you want to search your current directory only, add -maxdepth 1 to your find command.
  • Pipe into awk '{print $2, $1}' to show the count after the extensions.
share|improve this answer
    
Nice answer. This will not include files without extensions. Is there a simple way to find that? –  jaychris Sep 4 '13 at 17:02
    
The -name '*.*' option restricts find to files with extensions only. If you leave this out, you'll end up with a count of 1 for every file though, so this might not be ideal. –  slhck Sep 4 '13 at 17:03
    
You could add a branch in the sh to check if it has an extension, if so print extension, if not print full filename; and find * –  Clayton Stanley Sep 5 '13 at 5:27
    
@ClaytonStanley Since the extra sh process takes a little more execution time, filtering the results with find will be a little faster, I guess. –  slhck Sep 5 '13 at 5:45

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.