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I have batch file that generates one file *.txt that I use for review some details about installation process of a software, all good BUT how can I generate a new *.txt file on the same location with a different name or number?

For example: If folder C:\Users\John\Documents contains a file named ProgramLog.txt I need that the name of a new change to *.txt eg. Programlog1.txt and so on (leaving the ProgramLog.txt in the same location)

Sorry here is my batch:

msiexec /i "C:\Windows\System32\John.msi" /passive /log c:\Programlog.txt 

I added this, renames and add an extra character (number one) but overwrites the file:-(

FOR %%a IN (*.txt) DO CALL:processFile "%%~a" 

SET /a fileCounter+=1 
SET "fileName=%~n1%filecounter%%~x1" 
IF EXIST "C:\Users\%username%\Desktop\%fileName%" GOTO:loop 
ECHO MOVE "%~1" "C:\Users\%username%\Desktop\%fileName%" 
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How are the current files being generated? changing the output in batch is just > filename –  50-3 Sep 9 '13 at 20:35
Why don't you supply the relevant part of your batch file that makes the file, and then someone can amend it to rename the file if needed. –  paradroid Sep 9 '13 at 20:40
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1 Answer 1

Do you really need to keep the first file named ProgramLog.txt?  This would be simpler if you would just rename the first file to ProgramLog1.txt, the second one to ProgramLog2.txt, etc.  Because saying

msiexec … /log c:\ProgramLog.txt

is going to overwrite an existing file called ProgramLog.txt.

If you must do it this way, change the msiexec command to

msiexec … /log c:\temp.txt

and then rename temp.txt to ProgramLog.txt the first time, ProgramLog1.txt the second time, ProgramLog2.txt the third time, etc.  Alternatively, do your original command:

msiexec … /log c:\ProgramLog.txt

the first time (when ProgramLog.txt doesn’t exist), and on all subsequent runs create temp.txt and rename it.

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