Super User is a question and answer site for computer enthusiasts and power users. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I'm working on a video hosting project and I would like to know if I'm converting my videos quality the right way.

my equation is: newY=(y/x)*newX

so 1080p is:

   than 720p

My problem is 360 and below comes out in a terrible quality. comparing that to youtube I'm wondering if they are actually changing the video resolution or just changing the kb/s?

share|improve this question
I'm a little confused by your question. 1080p is 1920x1080 (WxH), and 720p is 1280x720. 360p would be either 480x360 (for 4:3) or 640x360 (for 16:9). What's your equation supposed to be calculating for you? – Ƭᴇcʜιᴇ007 Sep 26 '13 at 18:34
You're only dealing with the spatial resolution, not the quality which is affected by many factors like compression level. – sawdust Sep 26 '13 at 18:41
You shouldn't expect good quality at lower resolutions. I mean 360p on YouTube is horrible quality. – Ramhound Sep 26 '13 at 18:47
up vote 6 down vote accepted

1080 describes the vertical resolution of a video. In your question you're using it as the horizontal resolution. As techie mentioned in the comments, common video resolutions include:

  • 1920 x 1080
  • 1280 x 720
  • 720 x 480
  • 480 x 360
  • 640 x 360
share|improve this answer
Yep, I should have checked myself better I was sure 1080p is the X... – user2783132 Sep 26 '13 at 19:51

Use x264 (an H.264 encoder) with constant quality.

In x264, this mode is called Constant Rate Factor. Lower values mean better quality. Use around 19–22 for very good quality. The default is 23.

Convert your video with Handbrake, VidCoder, Ripbot264, TEncoder, FFmpeg, etc.

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.