You can try
start /MAX yourscript.bat to start your script in a maximized cmd (up to Windows 7)
Edit (by Rik):
I've created a small example which shows how you could do it all in one batch-file
(without a separate launcher):
if not "%1" == "max" start /MAX cmd /c %0 max & exit/b
:: here comes the rest of your batch-file
There will be a slight flicker of the original batch-file (which will exit immediately) before starting the maximized version.
If the batch is not called with the parameter
max we call itself again (
%0), this time maximized with the help of
start /max, and with the parameter
max and that way the second time its called it will skip the if-statement and continue with your commands.
if not "%1" == "max" execute the next command only if
%1 is not "max".
%1 stands for the first parameter given to the batch-file. So
my_batch.bat max will have
max in the
%1-variable. If we didn't start the batch with a
max parameter we need to execute this line.
start /MAX start the command after it, in maximized form.
cmd /c execute
/c means exit afterwards.
%0 max. The
%0 stands for your own batch-file name and here
max is its first parameter. This means we need to skip that first
if-line or else we get caught in a loop :)
& exit/b: The
& means execute the next command simultaneous with the previous. This means we executed the
start /max your batchfile and in the meantime exit the current batch.
This also means we can't call this version with any other parameters than
max. If your batch-files needs a parameter to start then you'll need to do some more magic (like
shifting the %1 after testing).
If that's the case let us know.