I am confused about the meaning of 192.168.x.x (private network). In DSL bridge mode, my computer has been assigned an IP as part of ISP's private network such as 36.82.x.x. It also can connect to the outside world through an public IP.
In LAN, 192.168.1.1 will be my router, 192.168.1.x is another computers connected to the router (as assigned by DHCP server).
I would like to know what is the rule if I connect to DSL network? I can still see 192.168.1.1 but this is not my own router. Scanning this range shows that there are also several live IPs such as 192.168.1.161, 192.168.1.162, etc. They are not part of my private network.
nmap scan to
192.168.1.0/24 while in bridging mode. I can see several IPs are alive which are not mine. I don't know much about how bridging to ISP works, but I assume that after bridging,
192.168.x.x are not my private network.
# ip addr 1: lo: <LOOPBACK,UP,LOWER_UP> ... link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 inet 127.0.0.1/8 scope host lo 2: eth0: <NO-CARRIER,BROADCAST,MULTICAST,UP> ... ... 3: wlan0: <NO-CARRIER,BROADCAST,MULTICAST,UP> ... ... 5: eth1: <BROADCAST,MULTICAST,UP,LOWER_UP> ... link/ether f8:d1:11:bc:9f:06 brd ff:ff:ff:ff:ff:ff inet6 fe80::fad1:11ff:febc:9f06/64 scope link valid_lft forever preferred_lft forever 6: ppp0: <POINTTOPOINT,MULTICAST,NOARP,UP,LOWER_UP> ... link/ppp inet 125.164.x.x peer 125.164.x.x/32 brd 125.164.x.x scope global ppp0 # traceroute 192.168.1.1 traceroute to 192.168.1.1 (192.168.1.1), 30 hops max, 60 byte packets 1 125.164.xx.1 2 125.164.xx.1 3 118.98.xx.xx 4 61.94.xx.xx 5 61.94.xx.xx 6 118.98.xx.xx 7 118.98.xx.xx 8 192.168.1.1
It requires 8 hops to reach 192.168.1.1.