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When windows starts I see most of the processes start in normal priority. I can manually change the priority of a running process. But what I want is when a particular process starts it be automatically set to run in high priority.

How is that possible?

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You can start a process in high proirity in command line. Use the start command.

start ["title"] [/dPath] [/i] [/min] [/max] [{/separate | /shared}] [{/low | /normal | /high | /realtime | /abovenormal | belownormal}] [/wait] [/b] [FileName] [parameters]

eg:- start "Explorer" /high "C:\Windows\explorer.exe" For easy access type this into a notepad and save as file with "bat" extension. Then you only have to double click this file

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I understand we can definitely set priority using command line. But what I want it to to automate the process, and no user action needs to be required. I am thinking that I can store the .bat file somewhere and tell windows to execute it automatically at logon. Does it make correct sense? – Bishnu D. Jan 10 '14 at 7:43

Right click and drag the file to the startup folder under the start menu, and create a shortcut there. Windows automatically runs anything under the startup menu upon logon.

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1  
The question was rather how to start process in high priority, not how to start it upon logon. – kenorb Sep 18 '15 at 0:04
    
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post - you can always comment on your own posts, and once you have sufficient reputation you will be able to comment on any post. – JakeGould Sep 18 '15 at 1:18

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