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This question already has an answer here:

I occasionally need to run a command such as:

mv "very-long-file-name.x" "very-long-file-name.y"

I would like to achieve this without repeating the very long file name twice...

I know how to do this by passing just "very-long-file-name" once to a bash script which would then use $1 ... but how can I do this without a script?

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marked as duplicate by slhck Jun 1 '14 at 7:13

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

up vote 3 down vote accepted

bash lets you define variables before the command, like this:

X="very-long-file-name" bash -c 'mv "${X}.x" "${X}.y"'

But beware that variables defined this way are only defined for the environment that command runs in, not in the parent shell environment. So you have to have that bash -c in there, and put single-quotes around the the subshell argument string, otherwise the variables will be interpreted in the parent shell, where they're not defined.

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running exactly this in the OS X terminal I'm getting: mv: rename .x to .y: No such file or directory – GJ. Jun 1 '14 at 7:59
however, this works: export X="very-long-file-name" && mv "${X}.x" "${X}.y" – GJ. Jun 1 '14 at 8:01
@GJ. Oops, I'd forgotten that that syntax trick only defines the variable for the subshell. I've updated my answer to fix it. – Spiff Jun 2 '14 at 0:40

Make use of Brace Expansion:

mv very-long-file-name.{x,y}

Do not quote the {x,y} part. Do not add a space before or after any brace or the comma.

After expansion, this will result in:

mv very-long-file-name.x very-long-file-name.y
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