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Jun
3
comment My computer is eating hard drives
Was the first drive SSD also?
Mar
22
revised How to generate a valid random MAC Address with bash shell
added 532 characters in body
Mar
22
comment How to generate a valid random MAC Address with bash shell
Could be easily reworked to use 16 instead of 255 and generate the zero placeholder. It's just more lines...
Mar
22
comment How to generate a valid random MAC Address with bash shell
It was just something I threw out there since the OP was insisting on bash. You're saying you can't figure out how to pad the single digits with a zero right? @BrunoFinger
Sep
13
awarded  Quorum
Sep
6
awarded  Yearling
Jul
16
comment How resistant is BitLocker against brute force attacks on the 48 character recovery key?
It doesn't. The limitations on the blobs in the keyspace make it vastly different than bruteforcing AES
Jul
15
comment How resistant is BitLocker against brute force attacks on the 48 character recovery key?
Good luck. I hope you prove it wrong intead :)
Jul
15
comment How resistant is BitLocker against brute force attacks on the 48 character recovery key?
If you made a separate answer with math that went to the same place, I would upvote yours and delete mine. It was just something that needed saying.
Jul
15
comment How resistant is BitLocker against brute force attacks on the 48 character recovery key?
Then you run the numbers. When you find out I'm right, come back and remove the downvote :)
Jul
15
comment How resistant is BitLocker against brute force attacks on the 48 character recovery key?
How about - While a datacenter grinding Windows bitlocker credentials would be exponentially more likely to succeed than a datacenter grinding BSD FDE solution credentials. The scope of datacenter and reasonable timeline are both inspecific, but comparatively one is clearly superior to the other. Given something like an NSA datacenter, CPU-years on current hardware are no longer valid given parallel programming acceleration through a given GPU or a GPU farm.
Jul
15
comment How resistant is BitLocker against brute force attacks on the 48 character recovery key?
The math is that each "word" in the keyspace is limited in and of itself. I can't find the research paper that expresses that, but I'm sure I read it. Mathematically limiting each word exponentially reduces the keyspace when you stack one after another. Conversely, if you don't have the key, in the BSD keysystem, you don't even know if you're testing against accurate key material. Percentages aren't necessarily required once you grasp those two concepts.
Jul
12
awarded  Enlightened
Jul
12
awarded  Nice Answer
Sep
6
awarded  Yearling
Aug
25
comment How do I create an administrator user on Ubuntu?
I shared your question in the Ubuntu room since it is more correct. The only thing I might add is that libvirtd is not a default group for a clean install. The rest are.
Aug
25
awarded  Altruist
Aug
24
awarded  Investor
Aug
24
comment How do I create an administrator user on Ubuntu?
You might want to add that if you're doing this on desktop, current LTS also puts the initial admin user in some other groups as well. adm, cdrom, sudo, dip, plugdev, lpadmin, and sambashare on a clean install with cat /etc/group | grep testing | cut -f 1 -d :
Mar
19
awarded  Revival