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revised Why doesn't echo support “\e” (escape) when using the -e argument in MacOSX
fix title: it's the bash builtin echo, not /bin/echo
Sep
5
awarded  Scholar
Sep
5
accepted Why doesn't echo support “\e” (escape) when using the -e argument in MacOSX
Sep
5
comment Why doesn't echo support “\e” (escape) when using the -e argument in MacOSX
Of course -- thanks for noticing. I fixed the question to reflect this.
Sep
5
revised Why doesn't echo support “\e” (escape) when using the -e argument in MacOSX
Correction: This is about the Bash builtin echo, not /bin/echo
Sep
5
comment Why doesn't echo support “\e” (escape) when using the -e argument in MacOSX
I wasn't aware of $'string' being escape sequence -enabled, thanks.
Sep
5
comment Why doesn't echo support “\e” (escape) when using the -e argument in MacOSX
\x1B instead of \e does work, thanks.
Sep
5
comment Why doesn't echo support “\e” (escape) when using the -e argument in MacOSX
\033 instead of \e does work, thanks.
Sep
1
answered Why doesn't echo support “\e” (escape) when using the -e argument in MacOSX
Sep
1
asked Why doesn't echo support “\e” (escape) when using the -e argument in MacOSX