Schedule a job with at command

Question

Hello I have written a script and I want to schedule it to run at a certain time with the at command. I also want to use an argument in order to pass the time I want in the script so it can be executed at a specific time. The script's name is displaydir and it has the following arguments:

./displaydir dir1 09:00 AM

The script:

#!/bin/bash
at $2 $3
ll $1
cp ./$1/ ./dir2
exit 0

Answer 1

From the command line and the script I gather that your want your directory listing to happen at nine AM. This can happen with the following command:

at 9am -f displaydir

with the following script (displaydir):

#!/bin/bash
ll dir1
cp ./dir1/ ./dir2
exit 0

Answer 2

I have updated your script as follows;

at ${2} <<ENDOFFILE
ls -l $1
cp $1/* $3/
exit 0
ENDOFFILE

Run the script at below;

./displaydir dir1 "09:00 AM" dir2

I have added "*" in the copy command and also taking destination at an argument to the script, you can add -r to cp command if you want to recursively copy everything in that directory