I am looking to use the command line 7-Zip to unzip a folder.
I have a file, say example.zip
and want to unzip the contents of the file into a folder called example
.
What are the commands I need to do this?
I am looking to use the command line 7-Zip to unzip a folder.
I have a file, say example.zip
and want to unzip the contents of the file into a folder called example
.
What are the commands I need to do this?
7z x example.zip -oexample
Usage: 7z <command> [<switches>...] <archive_name> [<file_names>...]
[<@listfiles...>]
<Commands>
...
x: eXtract files with full paths
<Switches>
...
-o{Directory}: set Output directory
Edit:
7z x *.zip -o*
extracts all *.zip archives to subfolders with names of these archives.
Strangely, I had to go to the full help file to find this example; it isn't shown for 7z /?.
7z x
extracts with full paths; if you want to extract to current directory (ignore path info in the archive) use 7z e
. i find both handy at different times.
Jan 14, 2010 at 19:06
The syntax would be: 7z x <path to>\duane.zip -oc:\duane
This will extract the content of the archive duane.zip
to the folder c:\duane
with full paths.
Note: There is NO space between the switch -o
and the destination folder. If that folder does not exist, it will be created automatically.
Recursively extract a single file, or a selective set of files from an archive into the current folder:
7za.exe e art.archive -ir!*Art.jpg
Without 7-zip powershell v3+ can extract a zip file:
Expand-Archive "Source" "Destination"