Firstly I'm a beginner so please forgive me.
I can't quite figure out how to do this as I've only ever been taught how to assign IP addresses with the address space of xxx.xxx.xxx.xxx/24 which makes sense to me because you're only dealing with the last octet. But with /23 you're dealing with two octets aren't you?
E.g 192.168.10.0/23 is..
192.168.0000 1010. 0000 0000
Where the last 0 in the 3rd octet is included in the subnet mask.
So to make things more clear in my head, is someone able to show me an example of assigning 256 IP addresses ?
Below is the full question. Please don't fully answer the question, I would just like a push in the right direction.
As part of restructuring at the Cyber University, a new Faculty of Innovation has been established. The faculty encompasses Computer Science and Engineering disciplines. You have been tasked to design the network for the new faculty. The Default_Gateway and Router01 are part of the existing network, and the faculty has been assigned 18.104.22.168/23 address space.
Divide the assigned address space between faculty admin, CS and ENG subnets such that the ENG subnet gets 256 IP addresses, Faculty Admin and CS subnets get 128 IP addresses each.