What I want to do:
- write a batch script to do the following
- loop though all dir starting with "01-"...
- Check if "Pictures" folder is empty or not. skip rest folders
- If "Pictures" folder is Empty, than print path of empty "Pictures" folders.
Output Example:
MainFolder/01-Folder3/Pictures is empty
Structure of my folder:
- 1st lvl... Every thing inside my "MainFolder"
- 2nd lvl... all folders start with a number ex: 01, 02, 03, etc...
- 3rd lvl... There is folder called "Pictures"... in every 3rd lvl
here is an example:
|>MainFolder
|--->01-Folder1
|------->Pictures
|----------->pic.png
|----------->SubPicFolder
|------->RandomFolder1
|------->RandomFolder2
|--->01-Folder2
|------->Pictures
|----------->SubPicFolder
|------->RandomFolder1
|--->01-Folder3
|------->Pictures
|------->RandomFolder1
|--->02-Folder1
|------->Pictures
|------->RandomFolder1
|------->RandomFolder1
What I have tried?:
@echo off
for /d /r %%A in ("Pictur*") do (
dir /a /b "%%~fA" 2>nul | findstr "^" >nul || echo %%~fA
)
pause
Problem with what I have tried:
This code does print all empty "Pictures" folder but issue is that it checks all the folder. I just want to check folder starting with "01-" and subfolder "Pictures". skip rest.