AHK — How to interrupt alternate keys for same hotkey?

Question

I have a code that every time I press the hotkey, a letter is sent.

Pressing Q, Q, Q, Q, Q is sent "a", "b", "c", "d", "e", respectively. Then the loop restarts.

For example: pressing Q 13 times sends "abcdeabcdeabc".

My question is:

How can I reset the loop and return to the first letter ("a") if I do not press Q for a few seconds?

My code:

q::
Send, % ["a","b","c","d","e"][(count >= 5 || !count)? count := 1 : ++count]
return

Your question is difficult to understand. What do you mean by [ Combo Break ]? How should AHK respond if you intend to press Q three times, but pause after the first keypress (should it send a)? — I say Reinstate Monica, Sep 22, 2017 at 20:30
Excuse me. This was really confusing. Let me try to explain: Every time I press Q, a letter in the loop is sent. Example: pressing Q, Q, Q, Q, Q, Q, Q, Q = sends "a", "b", "c", "d", "a", "b", "c", "d". What I needed was a way to reset the loop if I did not press Q for a while. Example: pressing Q, Q, Q, (so do not press Q for few seconds), and then Q again = "a", "b", "c", (after idle), "a" again (not "d"). The loop restarted after idle. — rdllngr, Sep 22, 2017 at 21:04
That makes a lot more sense! Please consider editing your question so that others can benefit from the answer you found. — I say Reinstate Monica, Sep 22, 2017 at 21:51

rdllngr · Accepted Answer · 2017-09-22 23:04:46Z

2

I found a solution by myself. I hope this can help someone in the future.

Good luck. :)

q::
Send, % ["a","b","c","d","e"][A_TimeSincePriorHotkey>2500 || A_PriorHotkey<>A_ThisHotkey || (count >= 5 || !count) ? count := 1 : ++count]
return

answered Sep 22, 2017 at 20:18

rdllngr

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