Run a script with bash and supply a termination time [duplicate]

Question

Is it possible to run a script from bash (e.g. python) with a termination time, meaning that if this script runs for longer than X seconds, terminate it?

Answer 1

Yes, It is possible to run a bash script with a timeout for it's termination. You can do it by :

1. Using timeout :

It runs a command with a time limit. General syntax includes :

timeout signal duration command/script arguments

where :

• signal is Signal name or corresponding number. See man 7 signal
• Duration is Timeout specified in numbers with suffix as s for seconds , m for minutes , h for hours , d for days.

• Default is seconds, When you only specify just a number. As an example say you want to terminate your script after 2 minutes, then :

  timeout 2m /path/to/script arg1 arg2
  

• NOTE : Default timeout signal is SIGTERM for which some processes does not terminate. In that case we need to use SIGKILL signal to kill the process.

      timeout -s KILL 2m /path/to/script arg1 arg2
  

  OR

      timeout -k 30 2m /path/to/slow-command arg1 arg2
  

  In this case, timeout first sends the SIGTERM signal after initial timeout of 2 minutes. Then, waits for another timeout of 30 seconds and sends a SIGKILL to the process if it’s still running.

2. I don't have timeout command :

Well, There are many alternatives or workarounds, If for some reason you are unable to use timeout. These are :

1. Condition sleep then kill :

      /path/to/script arg1 arg2 & sleep 2m ; kill $!
   

2. Perl Alarms (This can be used within a sequential script.) :

      perl -e "alarm 120; exec @ARGV" "/path/to/script arg1 arg2"
   

3. Using expect command :

      time_out=120
      command="/path/to/script arg1 arg2"
   
      expect -c " set echo \"-noecho\";
                  set timeout $time_out;
                  spawn -noecho $command;
                  expect timeout { exit 1 } eof { exit 0 } "
   

Feel free to add-in more details.