In cmd can be used command mkdir /data/rs1 /data/rs2 /data/rs3 like: cmd example

Everything is correct:

folders example

But how to realize it in powershell?

I'm trying to use quotes, for example: powershell

With quotes I'm getting just one folder and having the issue in powershell: folders example

mkdir : Could not find part of the path "rs3".
строка:1 знак:1
+ mkdir "/data/rs1 /data/rs2 /data/rs3"
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    + CategoryInfo          : WriteError: (C:\data\rs1 \data\rs2 \data\rs3:String) [New-Item], DirectoryNotFoundException
    + FullyQualifiedErrorId : CreateDirectoryIOError,Microsoft.PowerShell.Commands.NewItemCommand

Without qoutes also the issue and haven't any folders folders example: powershell

mkdir : Can not find a positional parameter that takes an argument"/data/rs2".
строка:1 знак:1
+ mkdir /data/rs1 /data/rs2 /data/rs3
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    + CategoryInfo          : InvalidArgument: (:) [mkdir], ParameterBindingException
    + FullyQualifiedErrorId : PositionalParameterNotFound,mkdir

To avoid the issues, I can write without spaces:

PS C:\data> mkdir /data/rs1/data/rs2/data/rs3

But it will be one folder rs1 that contains inside rs2 and rs3:


I appreciate any help.


There are a lot of ways doing this in powershell

1..3 | ForEach {MD ".\data\rs$_"}


'RS1','RS2','RS3' | % {New-Item -Name ".\data\$_" -ItemType 'Directory'}


for ($i=1;$i -le 3;$i++){MD ".\data\rs$i"}


MD .\data
Pushd .\data
$Folder = @('RS1','RS2','RS3')
Md $Folder

Where md is an alias for New-Item and
%,ForEach are aliases for ForEach-Object

| improve this answer | |
  • Thanks, solved by using first variant. In my case it was PS C:\data> 1..3 | ForEach {MD "rs$_"} – invzbl3 Jul 8 '18 at 14:12
  • pushd is an alias for push-location and puts the current item to the top. Probably you do not need it but I am not sure. Maybe in the last solution a simple $ar='f1','f2',.. would also work. – Timo Oct 11 at 12:46

mkdir can create multiple directories in one go, so no need for foreach. you just have to spearate them by commas:

Here I created 3 folders (Hello, Hello2, Hello3) in a directory

PS C:\install> mkdir Hello,Hello2,Hello3

    Verzeichnis: C:\install

Mode                LastWriteTime         Length Name
----                -------------         ------ ----
d-----       09.07.2018     10:39                Hello
d-----       09.07.2018     10:39                Hello2
d-----       09.07.2018     10:39                Hello3

Here I created 3 folders on separate subfolders in a directory:

PS C:\install> mkdir .\xy3\Hello, .\yz3\Hello2, .\tr3\Hello3

    Verzeichnis: C:\install\xy3

Mode                LastWriteTime         Length Name
----                -------------         ------ ----
d-----       09.07.2018     10:42                Hello

    Verzeichnis: C:\install\yz3

Mode                LastWriteTime         Length Name
----                -------------         ------ ----
d-----       09.07.2018     10:42                Hello2

    Verzeichnis: C:\install\tr3

Mode                LastWriteTime         Length Name
----                -------------         ------ ----
d-----       09.07.2018     10:42                Hello3
| improve this answer | |

You could use foreach in PowerShell to get this done

ForEach ($Dir in ("Dir1", "Dir2", "Dir3", "Dir4"))
        New-Item -ItemType Directory -Path [PATH]\$Dir

Read more about ForEach in PowerShell

| improve this answer | |
  • While the parentheses enclosing the collection entries ease reading, they are not required. I do like ss64.com but the Get-Help about_foreach or docs.microsoft.com are more detailed. – LotPings Jul 8 '18 at 14:35

First of all, please don't use screenshot for things you can easily copy-paste as text.

The command in your screenshot is this:

mkdir \data\rs1 \data\rs2 \data\rs3

And this will work just fine in a script too, provided you are on the correct drive, in this example C:.

The command mkdir /data/rs1 /data/rs2 /data/rs3 is not the same thing, because as you can see, as the path parameters use / as path separator, which will not work in Windows.

Putting double-quotes around the list of paths doesn't help either. That way the double-quoted expression is treated as one single path, rather than 3 paths.

In short, just as mkdir \data\rs1 \data\rs2 \data\rs3 works in your command example, it works exactly the same way in a batch script.

| improve this answer | |

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