0

Example input:

void C::foo()
{ // <- this changes bracket balance from 0 to 1
    if (true)
    { // balance is 2 after we process this bracket
       ...
    } // now it is 1 again
} // now bracket balance is zero again, so next opening brace will be 
  // subsituted

Output

void C::foo()
{ PROCESSED;
    if (true)
    { 
        ...
    } 
} 

I have sed and awk at my disposal. Currently I know how to do the substitution in a very generic way thanks to the answer here How to edit a multiline pattern in bash (sed and awk are available), but I do not know how to catch the described curly braces.

1
awk -F "" '{
   for (i=1;i<=NF;i++) {
      if ($i == "}" && count > 0) count--
      if ($i == "{" ) if (count++ == 0) $i="{ PROCESSED;"
      printf "%s", $i
      }
   printf "%s", ORS
   }'

I used this approach to parse each line character by character.

Notes:

  • The logic does not allow count to reach negative values.
  • (count++ == 0) increases the count after comparing to 0.
  • ORS is the output record separator, by default a newline.
  • The code doesn't care about quoting, escaping, comments etc.
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