1

I tried saving image from my webcam, since strftime in ffmpeg 4.2.2 does not provide microseconds, to avoid overwriting the image in the same seconds, I plan to use both strftime and sequence number.

ffmpeg -i /dev/video0 -f image2 "%04d.jpg"

gives 0001.jpg, 0002.jpg

ffmpeg -i /dev/video0 -f image2 -strftime 1 "%F_%H-%M-%S.jpg"

gives 2020-07-25_01-02-03.jpg, 2020-07-25_01-02-04.jpg ...

ffmpeg -i /dev/video0 -f image2 "%F_%H-%M-%S_%%04d.jpg"

gives 2020-07-25_01-02-03_%04d.jpg, 2020-07-25_01-02-04_%04d.jpg ...

I would expect the %%04d will be replaced with numbers, but it does not. Is there any other solution?

0

I belive the command you entered, look like this:

ffmpeg -i /dev/video0 -f image2 "$(date +"%Y_%m_%d_%I_%M_%%d").jpg"

According to manpage date command can give you a nanoseconds (not microseconds). Use following command as a possible solution:

ffmpeg -i /dev/video0 -f image2 "$(date +"%Y_%m_%d_%I_%M_%S_%N").jpg

2
  • Thanks for the answer. Inject the date by shell command will cause all filename saved using the same date that the command first start. What I am going to achieve is naming the filename at the moment of saving. – Explosive pen Jul 25 '20 at 15:20
  • I didn't get the question right. FFMpeg can use strftime c++ function for output filename. But strftime function can't show microseconsds or similair value (cplusplus.com/reference/ctime/strftime). All I can afford is to use frame number ("%04d.jpg"). It seems you cant combine strftime 1` and standart filename pattern. – anex5 Jul 25 '20 at 17:00

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.