How to add import content of a hyperlink to the title of that hyperlink with Regex?

Question

I have this link (HTML Links - Hyperlinks)

<p class="mb-40px"><a href="my-name-is-prince.html"></a></p>

I want to import the content from link, copy it, and put it again in front of </a> ?

The Output should be:

<p class="mb-40px"><a href="my-name-is-prince.html">My Name Is Prince</a></p>

My regex is almost good, can copy the link from o place to another, but I don't know how to get off the connecting line

FIND: (<p class="mb-40px"><a href=")(.*?)(.html">)(</a>)

REPLACE BY: \1\2\3\u\2\4

Answer 1

Such job can be done with PythonScript plugin in Notepad++

---

If it is not yet installed, follow this guide

• Create a script (Plugins >> PythonScript >> New Script)
• Copy this code and save the file (for example format.py):

import re

def format(match):
    lab = re.sub('-', ' ',match.group(2)).title()
    return match.group(1) + lab

editor.rereplace('(<p class="mb-40px"><a href="(.*?)\.html">)', format)

• Open the file you want to modify
• Run the script (Plugins >> PythonScript >> Scripts >> format)
• Done

Result for given example:

<p class="mb-40px"><a href="my-name-is-prince.html">My Name Is Prince</a></p>

Answer 2

My solution consists of two steps:

Step 1:

• Find: (<p class="mb-40px"><a href=")(.*?)(.html">)(</a>)
• Replace By: \1\2\3\u\2\4

Step 2.

• Find: (?-s)(\G(?!^)|html">)((?!</a).)*?\K[-]
• Replace By: \x20