Is there a nice way of checking if an array has an element in bash (better than looping through)?
Alternatively, is there another way to check if a number or string equals any of a set of predefined constants?
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Sign up to join this communityIn Bash 4, you can use associative arrays:
# set up array of constants
declare -A array
for constant in foo bar baz
do
array[$constant]=1
done
# test for existence
test1="bar"
test2="xyzzy"
if [[ ${array[$test1]} ]]; then echo "Exists"; fi # Exists
if [[ ${array[$test2]} ]]; then echo "Exists"; fi # doesn't
To set up the array initially you could also do direct assignments:
array[foo]=1
array[bar]=1
# etc.
or this way:
array=([foo]=1 [bar]=1 [baz]=1)
${array[$test1]}
is simple but has a problem: it won't work if you use set -u
in your scripts (which is recommended), as you'd get "unbound variable".
set -u
: davidpashley.com/articles/writing-robust-shell-scripts.html, blog.hashbang0.com/2010/05/18/robust-bash-scripts-part-one, openews.net/2012/bash-script-to-write-robust.
It's an old question, but I think what is the simplest solution has not appeared yet: test ${array[key]+_}
. Example:
declare -A xs=([a]=1 [b]="")
test ${xs[a]+_} && echo "a is set"
test ${xs[b]+_} && echo "b is set"
test ${xs[c]+_} && echo "c is set"
Outputs:
a is set
b is set
To see how this work check this.
env
to avoid ambiguities in aliases, progs and other functions that may have adopted the name "test". As above env test ${xs[a]+_} && echo "a is set"
. You can also get this functionality using double-brackets, the same trick then checking for null: [[ ! -z "${xs[b]+_}" ]] && echo "b is set"
There is a way to test if an element of an associative array exists (not set), this is different from empty:
isNotSet() {
if [[ ! ${!1} && ${!1-_} ]]
then
return 1
fi
}
Then use it:
declare -A assoc
KEY="key"
isNotSet assoc[${KEY}]
if [ $? -ne 0 ]
then
echo "${KEY} is not set."
fi
if ! some_check then return 1
= some_check
. So: isNotSet() { [[ ... ]] }
. Check my solution below, you can do it in a simple check.
You can see if an entry is present by piping the contents of the array to grep.
printf "%s\n" "${mydata[@]}" | grep "^${val}$"
You can also get the index of an entry with grep -n, which returns the line number of a match (remember to subtract 1 to get zero-based index) This will be reasonably quick except for very large arrays.
# given the following data
mydata=(a b c "hello world")
for val in a c hello "hello world"
do
# get line # of 1st matching entry
ix=$( printf "%s\n" "${mydata[@]}" | grep -n -m 1 "^${val}$" | cut -d ":" -f1 )
if [[ -z $ix ]]
then
echo $val missing
else
# subtract 1. Bash arrays are zero-based, but grep -n returns 1 for 1st line, not 0
echo $val found at $(( ix-1 ))
fi
done
a found at 0
c found at 2
hello missing
hello world found at 3
explanation:
$( ... )
is the same as using backticks to capture output of a command into a variable printf
outputs mydata one element per line @
instead of *.
this avoids splitting "hello world" into 2 lines) grep
searches for exact string: ^
and $
match beginning and end of line grep -n
returns line #, in form of 4:hello world grep -m 1
finds first match onlycut
extracts just the line number You can of course fold the subtraction into the command. But then test for -1 for missing:
ix=$(( $( printf "%s\n" "${mydata[@]}" | grep -n -m 1 "^${val}$" | cut -d ":" -f1 ) - 1 ))
if [[ $ix == -1 ]]; then echo missing; else ... fi
$(( ... ))
does integer arithmetic#!/bin/bash
function in_array {
ARRAY=$2
for e in ${ARRAY[*]}
do
if [[ "$e" == "$1" ]]
then
return 0
fi
done
return 1
}
my_array=(Drupal Wordpress Joomla)
if in_array "Drupal" "${my_array[*]}"
then
echo "Found"
else
echo "Not found"
fi
in_array
. Cheers
${ARRAY[@]}
should be used.
I don't think you can do it properly without looping unless you have very limited data in the array.
Here is one simple variant, this would correctly say that "Super User"
exists in the array. But it would also say that "uper Use"
is in the array.
MyArray=('Super User' 'Stack Overflow' 'Server Fault' 'Jeff' );
FINDME="Super User"
FOUND=`echo ${MyArray[*]} | grep "$FINDME"`
if [ "${FOUND}" != "" ]; then
echo Array contains: $FINDME
else
echo $FINDME not found
fi
#
# If you where to add anchors < and > to the data it could work
# This would find "Super User" but not "uper Use"
#
MyArray2=('<Super User>' '<Stack Overflow>' '<Server Fault>' '<Jeff>' );
FOUND=`echo ${MyArray2[*]} | grep "<$FINDME>"`
if [ "${FOUND}" != "" ]; then
echo Array contains: $FINDME
else
echo $FINDME not found
fi
The problem is that there is no easy way to add the anchors (that I can think of) besides looping through the array. Unless you can add them before you put them in the array...
grep "\b$FINDME\b"
). Probably could work with non-alphanumeric constants that have no spaces, with "(^| )$FINDME(\$| )"
(or something like that... I have never been able to learn what flavor of regexp grep uses.)