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How can I configure .jar files run on double-click in Windows 7?

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Open regedit.exe search for : HKEY_CLASSES_ROOT\jarfile\shell\open\command

Probably, you have in the value:"C:\Program Files\Java\jre7\bin\javaw.exe" -jar "%1" %* change it to "C:\Program Files\Java\jre7\bin\java.exe" -jar "%1" %*

(make sure that the path points to your actual java.exe, for it depends on the java version you have installed)

Good luck. It worked for me. ;-)

  • Actually it's not necessary to use javaw. java.exe is ok for me. But the whole command was missing. – user626528 Jun 7 '13 at 6:05
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Instructions for configuring the file assocations you'll need can be found here:

  jar : Java Glossary - Making Jar Files Double Clickable
  http://mindprod.com/jgloss/jar.html#ASSOCIATION

  • Buy a tool for this? You must be kidding. – user626528 Jun 7 '13 at 6:06
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What I did was to make a shortcut to the jar file and edit it to open "java -jar path/to/file.jar". It's the only workaround I have come up with.

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In Windows 7 64 you might also find the 32bit registry key:

HKEY_CLASSES_ROOT\jar_auto_file\shell\open\command

This key might be set to 32bit values ( "C:\Program Files\Java\jre7\bin\java.exe" -jar "%1" or alike) creating conflict with 64 bit version thus the issue, so adjust it to this value:

"C:\Program Files\Java\jre7\bin\javaw.exe" -jar "%1" %*

You should be good to go with double-clicking executable jar files without conflict, now.

Cheers

Bob Qwack

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