I'm looking to build a nice little RAID array for dedicated backups. I'd like to have about 2-4TB of space available, as I have this nasty little habit of digitizing everything. Thus, I need a lot of storage and a lot of redundancy in case of drive failure. I'll also essentially be backing up 2-3 computers'
/home folders using one of the "Time Machine" clones for Linux. This array will be accessible over my local network via SSH.
I'm having difficulties understanding how RAID-5 achieves parity and how many drives are actually required. One would assume that it needs 5 drives, but I could be wrong. Most of the diagrams I've seen have only yet confused me. It seems that this is how RAID-5 works, please correct me as I'm sure I'm not grasping it properly:
/---STORAGE---\ /---PARITY----\ | DRIVE_1 | | DRIVE_4 | | DRIVE_2 |----| ... | | DRIVE_3 | | | \-------------/ \-------------/
It seems that drives 1-3 appear and work as a single, massive drive (
capacity * number_of_drives) and the parity drive(s) back up those drives. What seems strange to me is that I usually see 3+ storage drives in a diagram to only 1 or 2 parity drives. Say we're running 4 1TB drives in a RAID-5 array, 3 running storage and 1 running parity, we have 3TB of actual storage, but only have 1TB of parity!?
I know I'm missing something here, can someone help me out? Also, for my use case, what would be better, RAID-5 or RAID-6? Fault tolerance is the highest priority for me at this point, since it's going to be running over a network for home use only, speed isn't hugely critical.