How to list files based on matching only part of their filename?

Question

I have many files in a folder for example

Kiran.txt
Kiran1.txt
Kiran221.txt
Kiran144.txt
Time.csv
Timer.csv
Timer2.csv
Timer444.csv
Timer266.csv
Account.sh
Account3.sh
Account3333.sh
Account3333.sh
Account333333.sh

From this directory, I want to know how I could use grep to display files based on part of their filename - for example those starting with "Account" or those ending in ".sh".

Answer 1

You can find

find -type f -name "Account*"

Alternative 2 (this might include folder as well)

ls -1 Account*

Alternative 3 (grep, this could include folder as well)

ls -1 | grep -E "^Account"

Answer 2

Use a wildcard (What is this wildcard?):

ls *.sh

The * will match anything before the ending .sh that you want. Use the other ls options for displaying, e.g. -l to make it a long listing. See man ls for more info about what you can do with it.

Note that ls would also list any directory ending with .sh, not only files.

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You can also use find to overcome this problem.

find . -type f -maxdepth 1 -name "*.sh"

This command only lists "real" files. Using find is something I'd recommend if you want to do something with the found files afterwards. You can do this with the -exec option.

Answer 3

The standard solution is a pipe:

ls | grep ^Account

With something as simple as "Files starting with Account", globs would also work:

ls Account*

but in general a grep is more powerful, and it doesn't run the risk of overflowing the maximum command line length if your folder is really, really full.

Answer 4

Use the following command

   ls *.sh