Using tee to pipe ls and grep output into tail command without a script

Question

I have an issue running through log files.

I'm looking to use ls to create a list of files in the log directory and grep to run through for the specific instances/times the file ran. I only want to have the last line of each file so I want the tail -1 command to run off the list of files grep provided.

I've tried multiple combinations of code that I've run across but have not had any luck so far; at this point it has become more of a curiosity than useful due to the amount of time I've spent on this. Below are a couple examples of the instances I have attempted:

ls | grep 2011_.._.._.._35_.* | tee >(tail -1)
ls | tee >(grep 2011_.._.._.._35_.*) | tail -1

Additionally, I would like to do this with a single command line if possible rather than creating a script and running a loop.

Answer 1

REVISED!

had overread that you only want the last line of each logfile ...

The command you need is xargs not tee:

 ls | grep '2011_.._.._.._35_.*' | xargs -n 1 -- tail -1

or

 ls -1 2011_??_??_??_35_* | xargs -n 1 -- tail -1

This calls the command tail -1 for each file that passes the grep command (1st case) or that is found by the ls command (2nd case). Note that this will not work if a file contains spaces or newline. If you need an answer for that case, add a comment.

EDIT For your comment:

ls -1 2011_??_??_??_35_* | xargs -n 1 -I FILE -- sh -c 'echo ; echo "FILE"; tail -1 "FILE"'

A little bit more complicated, but also handles files with spaces in the name.

Each "FILE" in the command sequence echo ; echo "FILE"; tail -1 "FILE" will be replaced by a line that ls outputs. This command sequence will be passed to a shell and then executed.