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I have a text file which contains about 50MB of text:

valA
valB
valC
valZ
valB

Whats the quickest way to:

  1. cat the file
  2. Display the unique appearences
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    You don't need to cat the file. You can just do uniq file.txt > uniq.txt which will probably be fastest instead of stdout.
    – squiguy
    Sep 14, 2012 at 0:27
  • seems like 'cat text.txt | uniq -c | sort -n ' may be the answer Sep 14, 2012 at 0:28
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    @Clustermagnet: You'd want to do sort first, then call uniq. Useless use of cat. Try: < text.txt sort -n | uniq -c
    – Steve
    Sep 14, 2012 at 0:30
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    @Clustermagnet: UUOC Award? It isn't clear that counts are wanted or needed, so sort -u text.txt? If counts are wanted, then sort text.txt | uniq -c works, optionally followed by sort -n to put the lines into frequency order. Sep 14, 2012 at 0:31
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    @squiguy: the file must be sorted before uniq works sanely. The input clearly isn't sorted. Sep 14, 2012 at 0:32

2 Answers 2

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One way using awk:

awk '!array[$0]++' file.txt

Results:

valA
valB
valC
valZ

Food for thought:

sort -u file.txt

valA
valB
valC
valZ

< file.txt sort | uniq

valA
valB
valC
valZ

< file.txt sort | uniq -u                 # only print unique lines

valA
valC
valZ

< file.txt sort | uniq -d                 # only print duplicate lines

valB
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1

sort text.txt | uniq -c | grep "^\s*1 "

  • you have to sort before uniq
  • grep those ones of count=1

notice valB is not unique here.

Edit

How could I miss there is -u for uniq: uniq -u yet use this silly way:)

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