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I have a bunch of files in a directory and want to 7zip each one into its own 7zip archive

So, for example, 1.csv, 2.csv, 3.csv will end up as 1.7z, 2.7z, 3.7z

Is this possible with a .bat file in Windows 7? I'm using 7zip 9.29 alpha

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This should do what you want (well, almost, 1.csv will be 1.csv.7z):

for %f in (*.csv) do "c:\program files\7-zip\7z.exe" a -t7z %f.7z %f

If you run this in a batch file you need to change %f to %%f.

Also, if the files 1.csv.7z already exist in the directory, you need to delete them first. The following command line should do that:

for %f in (*.csv) do del %f.csv
  • beautiful. needed a slight tweak (for named files, I'd like to keep it as generic as possible so others can use it), but i got it working ------------------ for %%f in (*.csv) do "c:\program files\7-zip\7z.exe" a -t7z "%%f.7z" "%%f" – warsong Sep 20 '12 at 14:47
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for /d %%X in (*) do "c:\Program Files\7-Zip\7z.exe" a "%%X.7z" "%%X\" -mx=9 -ms=on -md=26 -mfb=256
  • care to explain what it does? – Baarn Sep 20 '12 at 14:50
  • thanks, this one is even nicer, much neater output :) edit: oh erm oops. i think you got the wrong end of the stick, but good effort. – warsong Sep 20 '12 at 14:51
  • this is the folder version instead of files. mx9 is max compression. ms is solid archive. – jiggunjer Dec 1 '17 at 6:28

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