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I want to exclude some directories from searching files and than run the find command to find required files. I am using below command

find . -maxdepth 1 -type d | grep -E -i 'sensors' | grep -v '.test' | xargs find -name '*.java'

But it throws following error

find: paths must precede expression
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The first find will cause the second find to list everything twice unless you exclude the current directory as well. This happens because the output of the first find contains a period.

$ find -maxdepth 1 -type d -print0 |
   grep -z -v -Ee 'sensors|\.test' |
   xargs.exe -0 -I% find % -name '*.java' |
   sort
  ./dirz/3.java
  ./dirz/3.java
  ./foo/2.java
  ./foo/2.java
  ./moo/1.java
  ./moo/1.java

You're better off doing something like this instead:

$ find . -type f -name \*java | grep -v -Ee './(sensors|\.test)'
./dirz/3.java
./foo/2.java
./moo/1.java

Or even:

$ echo dirz foo moo | tr \  \\n  > .search-dirs

$ find `cat .search-dirs` -type f -name \*java
dirz/3.java
foo/2.java
moo/1.java
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Use xargs' -i option which like in find's -exec option replaces {} with the paths.

... | xargs -i find "{}" -name '*.java'
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You can do it directly in find; no need to involve grep or xargs.

With a directory structure like:

$ ls *
a_sensors_directory:
my_file.java  my_non_java_file.txt

a_sensors_directory.test:
my_file.java  my_non_java_file.txt

something_else:
my_file.java  my_non_java_file.txt

, this GNU find command will pick out files ending in .java in directories in the current working directory that contain the word sensors, but does not end in .test (if I interpreted your question correctly):

$ find -type f -ipath './*sensors*' -not -ipath './*.test/*' -iname '*.java'
./a_sensors_directory/my_file.java

man find should explain the switches clearly and probably better than I would.

Piping is powerful, but the base tools handle many scenarios by themselves in a more straightforward manner. This avoids unnecessary process forks and keeps subtle errors to a minimum.

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