When windows starts I see most of the processes start in normal priority. I can manually change the priority of a running process. But what I want is when a particular process starts it be automatically set to run in high priority.

How is that possible?

share|improve this question

You can start a process in high proirity in command line. Use the start command.

start ["title"] [/dPath] [/i] [/min] [/max] [{/separate | /shared}] [{/low | /normal | /high | /realtime | /abovenormal | belownormal}] [/wait] [/b] [FileName] [parameters]

eg:- start "Explorer" /high "C:\Windows\explorer.exe" For easy access type this into a notepad and save as file with "bat" extension. Then you only have to double click this file

share|improve this answer
    
I understand we can definitely set priority using command line. But what I want it to to automate the process, and no user action needs to be required. I am thinking that I can store the .bat file somewhere and tell windows to execute it automatically at logon. Does it make correct sense? – Bishnu D. Jan 10 '14 at 7:43
    
How do you call it when you want to do it at login @BishnuD.? I'd commend you call this entire process instead of just the process you want to start.... so start "whateverthisis#" /high /path/to/the/executable – djsmiley2k May 29 at 15:28

Right click and drag the file to the startup folder under the start menu, and create a shortcut there. Windows automatically runs anything under the startup menu upon logon.

share|improve this answer
1  
The question was rather how to start process in high priority, not how to start it upon logon. – kenorb Sep 18 '15 at 0:04

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.