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I'm having trouble understanding the following:

  1. This works:

    =SUMPRODUCT(N(A1:A10="Some text");B1:B10)
    
  2. This doesn't:

    =SUMPRODUCT(IF(A1:A10="Some text";1;0);B1:B10)
    

The N() function converts the TRUE and FALSE values the comparison operator returns to their numerical values, which is what the IF should be doing, but isn't. Tracing the calculation shows an error in the value returned by IF.

An example of my error and usage (the Office is in Portuguese, however):

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  • Don't IF functions needs , instead of ; ? So it should be if(A1:A10="Some text",1,0) ? – Darius Jan 12 '14 at 13:14
  • Are you sure the IF is returning an error? It's returning the required value for me. @Darius, depending on regional settings, Excel uses ; or ,. – Jerry Jan 12 '14 at 13:15
  • Actually it's the A1:A10 range giving the first #VALUE! error, that then propagates to the rest of the formula. But barry's answer seems spot on, although lacking in explanation as to why this behavior happens. – Doktoro Reichard Jan 12 '14 at 13:50
  • @DoktoroReichard Could you put some values in your question that reproduced that error? I can't see to get what you're getting. – Jerry Jan 12 '14 at 16:27
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In normal usage (like your first example) SUMPRODUCT doesn't need to be "array entered" but in some circumstances (like in your second example where you use an IF function) it does need "array entry"......so if you confirm the formula with CTRL+SHIFT+ENTER it will give the required results.

Note: in the specific situation shown SUMIF will be better

=SUMIF(A1:A10;"Some text";B1:B10)

  • The only logical reason I found as to the N function working without array formulation is that it internally creates an array, which is recognized by the SUMPRODUCT, which is something IF cannot do. By the comments, it appears this is only relevant in Excel 2003. As far as reasons go, this is a very weak one (which is why I'm not posting it as an answer), but it explains the behavior. – Doktoro Reichard Jul 4 '14 at 21:50

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