34

In zsh, I want to iterate over an associative array. I need both keys and values. But when I iterate over the associative array normally (for x in $assoc_array), I get only values.

All examples I've looked at show that, given a key, you can get its value from an associative array. My problem is getting the set of keys to begin with.

Does zsh support iterating over keys in an associative array?

1
  • If you have just a small list this might be an option: for i in a,b c_s,d ; do KEY=${i%,*}; VAL=${i#*,}; echo $KEY" XX "$VAL; done
    – math
    May 16, 2014 at 14:44

2 Answers 2

38

You can get both keys and values at once with this nifty parameter expansion:

for key val in "${(@kv)assoc_array}"; do
    echo "$key -> $val"
done

See Parameter Expansion Flags in the Zsh manual.

6
  • This is way simpler +1
    – TimSum
    Sep 12, 2017 at 5:53
  • 1
    This doesn't work when the keys or values have spaces in them
    – Max Coplan
    Sep 9, 2019 at 1:33
  • (@kv) is better (it works with quotes, too.).
    – HappyFace
    Oct 10, 2020 at 16:23
  • @HappyFace edited Oct 24, 2020 at 1:38
  • 1
    @Gairfowl edited Jan 23, 2021 at 17:14
39

I continued searching after asking my question and found this answer on the Unix StackExchange:

typeset -A assoc_array
assoc_array=(k1 v1 k2 v2 k3 v3)

for k in "${(@k)assoc_array}"; do
  echo "$k -> $assoc_array[$k]"
done

Output is:

k1 -> v1
k2 -> v2
k3 -> v3
3
  • 2
    For anyone wanting to test this in a useful way, try with the builtin $options. (See man zshoptions)
    – mVChr
    Oct 29, 2016 at 9:29
  • What if the key is not an increasing number like foo, bar, etc like arr[foo]=baz?
    – Timo
    Dec 17, 2017 at 20:28
  • 2
    @Timo I don’t think you should expect any specific order in associative arrays. Nov 7, 2020 at 23:55

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