I am trying to tackle the following subnetting problem: Prepare subnetting for an organization that requires 2000 hosts to be placed on the network. The maximum number of hosts on a subnetwork is 300. The organization doesn't need more then 24 subnetworks in the foreseen future. As a solution, for the first three subnetworks indicate the first and last host address in the subnet.
So far this is what I have come with: 9 bits will be needed for the host addresses and 5 for the subnet. Thus the remaining 18 bits are reserved for the network.
I think this will require class B addressing, so I choose to assign the following IP to the network: 22.214.171.124/18
Subnet 1: 1st host - 126.96.36.199, last host-188.8.131.52 | 184.108.40.206 and 220.127.116.11 I reserved for subnet address and broadcast respectively
Is this reasoning correct, will subnet 2 start at 18.104.22.168?