Is there any way to pass arguments via pipe on bash?

something like:

echo value1 value2 | mkdir -p ./$1/$2

The line above would create the directories ./value1/value2

If this is not possible I would accept suggestions.

Any help is appreciated.

up vote 2 down vote accepted

The following works in Unbuntu:

echo -e value1\\nvalue2|echo mkdir -p ./`line`/`line`

I can't guarantee that all bash implementations will read the lines in left-to-right order.

Alternatively:

echo value1 value2|( read p1 p2; echo mkdir -p ./$p1/$p2 )

This will work with all bash implementations, but will need elaboration if either value contains blanks.

(I have used echo mkdir to show the effect.)

  • The second alternative is perfect for what I'm doing, thanks! – guest9586 Dec 11 '14 at 18:51

How about

echo v1 v2 | awk '{print "./"$1"/"$2}' | xargs mkdir -p

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