CMD command to open a file using link

Question

Below is my batch file script

@echo off
setlocal enableextensions enabledelayedexpansion
for /f %%b in (C:\COST\Programlink.txt) do (
%%b
pause
)

And in the programlink.txt as mentioned in the above batch command I have the link of the file I want to open

"D:\COST\Mustafa Batch files\Batch files\1.txt"

But when I run the batchfile script it shows the below error

'"D:\COST\Mustafa' is not recognized as an internal or external command,
operable command or batch file.
Press any key to continue...

But when i enter the below command directly into the CMD prompt it works fine.

 "D:\COST\Mustafa Batch files\Batch files\1.txt"

I just want to open 1.txt file using my batch script I mentioned above. I can't identify my mistake. Please help me to right my batchfile.

Answer 1

I used the modified batchfile as below by using "usebackq delims=" and works well

@echo off
setlocal enableextensions enabledelayedexpansion
for /f "usebackq delims=" %%b in (C:\COST\Programlink.txt) do (
%%b
pause
)

But this is only one half of my batchfile. I shall proceed further and will come back if face any further problems.

And It has worked well.