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Facing the same problem as Why doesn't 'find' prune the way I think it should?,

but that accepted answer doesn't work for me:

Here are my files:

$ find . 
.
./resources
./resources/sitewide
./resources/sitewide/test.c
./resources/sitewide/.svn
./resources/sitewide/.svn/test.c
./resources/test.c
./resources/.svn
./resources/.svn/test.c
./test.c
./users
./users/avatars
./users/avatars/test.c
./users/avatars/.svn
./users/avatars/.svn/test.c
./users/test.c
./users/.svn
./users/.svn/test.c
./temporary
./temporary/test.c
./temporary/.svn
./temporary/.svn/test.c
./.svn
./.svn/test.c

This is what the result is when using the accepted answer:

$ find -type d -path '.svn' -prune -o -print
.
./resources
./resources/sitewide
./resources/sitewide/test.c
./resources/sitewide/.svn
./resources/sitewide/.svn/test.c
./resources/test.c
./resources/.svn
./resources/.svn/test.c
./test.c
./users
./users/avatars
./users/avatars/test.c
./users/avatars/.svn
./users/avatars/.svn/test.c
./users/test.c
./users/.svn
./users/.svn/test.c
./temporary
./temporary/test.c
./temporary/.svn
./temporary/.svn/test.c
./.svn
./.svn/test.c

There are two problem with the accepted answer, first the .svn are still listed, and second, not only directories but files are also listed.

These problems I actually can fix. but my question is,

how to find those .c files not under .svn directories?

I've tried all the following but nothing worked for me:

 find .  -path '*/.svn' -prune -name "*.c" -print
 find .  -path '*/.svn' -prune -o -name "*.c" -print
 find .  -path '*/.svn' -prune -name "*.c" -o -print
 find .  -path '*/.svn' -prune -a -name "*.c" -print

Please help.

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1 Answer 1

Reset to default
1

Your command

find .  -path '*/.svn' -prune -o -name "*.c" -print

should indeed work, though you might rewrite it

find .  -name .svn -prune -o -name "*.c" -print

otherwise your find is broken. I tried on 2 versions find --version: 

find (GNU findutils) 4.5.12
find (GNU findutils) 4.4.2
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3
  • 1
    Thanks meuh. More Q: The command that I actually ran was "find . \( -type f -o -type l \) -path '*/.svn' -prune -o -name "*.c" -print", but I remove that \( -type f -o -type l \) part to simplify my question (I also tried to put a -o before -path). Now I realize it is that part that is giving me the problem. Please add your answer to that as well. Thanks.
    – xpt
    Aug 11, 2015 at 14:26
  • 1
    Ah, got it -- find . -name .svn -prune -o \( -type f -o -type l \) -name "*.c" -print
    – xpt
    Aug 11, 2015 at 14:32
  • @xpt glad you found how to do what you wanted. The syntax is fairly painful. I find it useful to think there's an implied -a between all options and that and binds tighter than or.
    – meuh
    Aug 11, 2015 at 15:12

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