I have a DELL PRECISION M4400 running Windows 7 Professional.
Recently, the laptop started freezing and would go to sleep and would not be able to wake up unless a hard reset was given.
I downloaded and ran the DELL diagnostics from the DELL website which indicated a HDD failure. It was recommended to replace the HDD. I got the following (truncated) report (SMART) for the 320GB HDD.
WDC WD3200BEKT-75PVMT0-WD-WXL1A91U2336-TEST.mht HDDScan Drive Test Report Model: WDC WD3200BEKT-75PVMT0 Firmware: 01.01A01 Serial: WD-WXL1A91U2336 LBA: 625142448 Report By: HDDScan for Windows version 3.3 Report Date: 8/21/2015 1:08:33 AM Open Disk Test : RD-Read Executing Block start at 2428416 time 55ms . . Block start at 14633472 time 51ms Bad block found, start LBA : 19194880 Block start at 26177024 time 261ms . . Block start at 41292800 time 58ms Bad block found, start LBA : 46550528 Block start at 46551296 time 73ms Block start at 46551552 time 74ms Block start at 46554624 time 64ms Bad block found, start LBA : 46574592 Bad block found, start LBA : 46576384 Block start at 46576640 time 100ms . Block start at 46577920 time 112ms Bad block found, start LBA : 46578432 Bad block found, start LBA : 46582272 Block start at 46582528 time 273ms Block start at 46583040 time 64ms Bad block found, start LBA : 46586624 Block start at 46590720 time 84ms . . Block start at 46671104 time 59ms Bad block found, start LBA : 46672128 Bad block found, start LBA : 46675968 Block start at 46676224 time 154ms . . Block start at 618832128 time 107ms
From the report I understand that, only a portion of the hard drive has bad sectors only from the beginning (Bad block found, start LBA : 46675968 is the last one)
I'm planning to allocate till this as un-partitioned space and not use it. The question is how many GB's should I make as un-partitioned space so that I can continue to use my laptop.
I tried researching the internet for the meaning of LBA and its co-relation to hard drive size - all in vain. The Wiki page on LBA is of very little use in this context.
(Note: I do not mind losing data in case if the HDD fails suddenly. Just want to make the maximum out of this HDD)
From here, I understand that this formula which converts LBA to GB:
(LBA*512) / (1024^3)
By this formula: 46675968 / (1024^3) = 22.25GB - which I'd roundup as 25GB
Would this be correct?