1
Use the -u switch to only output the unique values.
who | cut -d " " -f 1 | sort | uniq -u
You need to sort the usernames, though, as uniq expects the input to be sorted. That's true for the -d solution, too, unless your version of who already groups the lines by user (and the one I have accessible (GNU 8.28) doesn't).
1
You need something like this:
res=`realm join -U admin $domain_name 2>&1`
if [[ $res == *"realm: Already joined to this domain"* ]]; then
echo done
exit 0
fi
1
$ echo hello | iconv -f ascii -t utf-16le | hexdump -C
00000000 68 00 65 00 6c 00 6c 00 6f 00 0a 00 |h.e.l.l.o...|
$ echo hello | iconv -f ascii -t utf-16le | od -t x1
0000000 68 00 65 00 6c 00 6c 00 6f 00 0a 00
The question is how 'od' handles endianness. When you're asking it to display units larger than a single byte (-x displays 16-bit ...
1
Any day of the year before the first Monday will be week 00. Take January 1 2020 for instance, which was a Wednesday (the first Monday of 2020 did not occur until January 6):
$ date -d "2020-01-01" +%W
00
$ date -d "2020-01-02" +%W
00
$ date -d "2020-01-03" +%W
00
$ date -d "2020-01-04" +%W
00
$ date -d "2020-01-...
1
Simeplest solution I could think of:
sort -u file1.txt file2.txt > result.txt
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